faktorisieren x^3+4x^2-21x

Lösung

faktorisieren

x^{3} + 4 x^{2} - 21 x

x (x - 3) (x + 7)

Schritte zur Lösung

x^{3} + 4 x^{2} - 21 x

Klammere gleiche Terme aus

x : x (x^{2} + 4 x - 21)

= x (x^{2} + 4 x - 21)

Faktorisiere

x^{2} + 4 x - 21 : (x - 3) (x + 7)

= x (x - 3) (x + 7)

∣ 4 - 5 a ∣ = ∣ 10 - 5 a ∣

9^{2} + b^{2} = 1 5^{2}

4 x^{2} - x - 5 \leq 0

x - 4 = x - 6

1 = 5