What are the solutions to the equation (x+3)(x-5)=0 ?

The solutions to the equation (x+3)(x-5)=0 are x=-3,x=5

Find the zeros of (x+3)(x-5)=0

The zeros of (x+3)(x-5)=0 are x=-3,x=5

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(x + 3) (x - 5) = 0

x = - 3, x = 5

Solution steps

(x + 3) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 5 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 5 = 0 : x = 5

The solutions to the quadratic equation are:

x = - 3, x = 5

k^{2} - 18 k - 19

\frac{1}{30} + \frac{1}{10}

4 x^{2} - 16 y^{2}

0 - 4 = 7 (x - 6)

ln (\frac{3}{2})

What are the solutions to the equation (x+3)(x-5)=0 ?
The solutions to the equation (x+3)(x-5)=0 are x=-3,x=5
Find the zeros of (x+3)(x-5)=0
The zeros of (x+3)(x-5)=0 are x=-3,x=5