log_{2}(x^2-7x)<3

Lösung

lo g_{2} (x^{2} - 7 x) < 3

- 1 < x < 0 or 7 < x < 8

Intervall-Notation

(- 1, 0) \cup (7, 8)

Schritte zur Lösung

lo g_{2} (x^{2} - 7 x) < 3

Wende die log Regel an

x^{2} - 7 x < 8 and x^{2} - 7 x > 0

x^{2} - 7 x < 8 and x^{2} - 7 x > 0 : - 1 < x < 0 or 7 < x < 8

- 1 < x < 0 or 7 < x < 8

s im pl i f y \frac{2 i}{4 - i}

6 x^{2} - 9 x + 4 = 0

f a c t or x^{2} - 3 x + \frac{9}{4}

(3 x - 6) (- x + 3) = 0

∣ 2 - x ∣ = 6