What are the solutions to the equation (x+1)^2=64 ?

The solutions to the equation (x+1)^2=64 are x=7,x=-9

Find the zeros of (x+1)^2=64

The zeros of (x+1)^2=64 are x=7,x=-9

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(x + 1)^{2} = 64

x = 7, x = - 9

Solution steps

(x + 1)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 64 : x = 7

Solve

x + 1 = - 64 : x = - 9

The solutions to the quadratic equation are:

x = 7, x = - 9

\frac{- 5 ( 50 ) + 249}{5 ( 5 ( 50 ) + 1 )}

5 x^{2} + 19 x - 4

8 n^{3} + 2 n^{2}

(\frac{8}{17})^{2} - (\frac{15}{17})^{2}

\frac{2}{3} \cdot 180

What are the solutions to the equation (x+1)^2=64 ?
The solutions to the equation (x+1)^2=64 are x=7,x=-9
Find the zeros of (x+1)^2=64
The zeros of (x+1)^2=64 are x=7,x=-9