faktorisieren x^2(x-3)+20

Lösung

faktorisieren

x^{2} (x - 3) + 20

(x + 2) (x^{2} - 5 x + 10)

Schritte zur Lösung

x^{2} (x - 3) + 20

Multipliziere aus

x^{2} (x - 3) + 20 : x^{3} - 3 x^{2} + 20

= x^{3} - 3 x^{2} + 20

Faktorisiere

x^{3} - 3 x^{2} + 20 : (x + 2) (x^{2} - 5 x + 10)

= (x + 2) (x^{2} - 5 x + 10)

f a c t or 12 a^{3} - 36 a^{2} - 21 a

x^{2} + 14 x + 58 = 0

2 x^{2} + x \geq 7

5 (x - 3) = 2 x + 6

78 = 7 t + 16 t^{2}