What are the solutions to the equation 5-10x-3x^2=0 ?

The solutions to the equation 5-10x-3x^2=0 are x=-(5+2sqrt(10))/3 ,x=(2sqrt(10)-5)/3

Find the zeros of 5-10x-3x^2=0

The zeros of 5-10x-3x^2=0 are x=-(5+2sqrt(10))/3 ,x=(2sqrt(10)-5)/3

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5 - 10 x - 3 x^{2} = 0

x = - \frac{5 + 2 10}{3}, x = \frac{2 10 - 5}{3}

Decimal Notation

x = - 3.77485 \dots, x = 0.44151 \dots

Solution steps

5 - 10 x - 3 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} - 10 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 3 ) \cdot 5}{2 ( - 3 )}

(- 10)^{2} - 4 (- 3) \cdot 5 = 410

x_{1, 2} = \frac{- ( - 10 ) \pm 4 10}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4 10}{2 ( - 3 )}, x_{2} = \frac{- ( - 10 ) - 4 10}{2 ( - 3 )}

x = \frac{- ( - 10 ) + 4 10}{2 ( - 3 )} : - \frac{5 + 2 10}{3}

x = \frac{- ( - 10 ) - 4 10}{2 ( - 3 )} : \frac{2 10 - 5}{3}

The solutions to the quadratic equation are:

x = - \frac{5 + 2 10}{3}, x = \frac{2 10 - 5}{3}

4 \cdot 4^{2}

- 2 + (- 3)

4 x - 7 < 2 x

λ^{2} - 5 λ + 3 = 0

x^{3} + 7 x

What are the solutions to the equation 5-10x-3x^2=0 ?
The solutions to the equation 5-10x-3x^2=0 are x=-(5+2sqrt(10))/3 ,x=(2sqrt(10)-5)/3
Find the zeros of 5-10x-3x^2=0
The zeros of 5-10x-3x^2=0 are x=-(5+2sqrt(10))/3 ,x=(2sqrt(10)-5)/3