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受欢迎的代数 >

化简 (8x^{24}y^{-12})^{5/3}

解答

化简

(8 x^{24} y^{- 12})^{\frac{5}{3}}

解答

\frac{32 x ^{40}}{y ^{20}}

求解步骤

(8 x^{24} y^{- 12})^{\frac{5}{3}}

使用指数法则:

(a \cdot b)^{n} = a^{n} b^{n}

(8 x^{24} y^{- 12})^{\frac{5}{3}} = 8^{\frac{5}{3}} (x^{24})^{\frac{5}{3}} (y^{- 12})^{\frac{5}{3}}

= 8^{\frac{5}{3}} (x^{24})^{\frac{5}{3}} (y^{- 12})^{\frac{5}{3}}

8^{\frac{5}{3}} = 32

= 32 (x^{24})^{\frac{5}{3}} (y^{- 12})^{\frac{5}{3}}

化简

(x^{24})^{\frac{5}{3}} : x^{40}

= 32 x^{40} (y^{- 12})^{\frac{5}{3}}

化简

(y^{- 12})^{\frac{5}{3}} : \frac{1}{y ^{20}}

= 32 x^{40} \frac{1}{y ^{20}}

化简

32 x^{40} \frac{1}{y ^{20}} : \frac{32 x ^{40}}{y ^{20}}

= \frac{32 x ^{40}}{y ^{20}}

流行的例子

x^{2} - 6 x = 9

∣ 4 x - 6 ∣ \leq 14

4 x - 12 > 6

-0.2(x+4)-0.1x=-2.6

- 0.2 (x + 4) - 0.1 x = - 2.6

化简 (16r^3t^{-5})/(4r^{-1)t^2}

s im pl i f y \frac{16 r ^{3} t ^{- 5}}{4 r ^{- 1} t ^{2}}