What are the solutions to the equation j^2+20j+43=0 ?

The solutions to the equation j^2+20j+43=0 are j=-10+sqrt(57),j=-10-sqrt(57)

Find the zeros of j^2+20j+43=0

The zeros of j^2+20j+43=0 are j=-10+sqrt(57),j=-10-sqrt(57)

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j^{2} + 20 j + 43 = 0

j = - 10 + 57, j = - 10 - 57

Decimal Notation

j = - 2.45016 \dots, j = - 17.54983 \dots

Solution steps

j^{2} + 20 j + 43 = 0

Solve with the quadratic formula

j_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 43}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 43 = 257

j_{1, 2} = \frac{- 20 \pm 2 57}{2 \cdot 1}

Separate the solutions

j_{1} = \frac{- 20 + 2 57}{2 \cdot 1}, j_{2} = \frac{- 20 - 2 57}{2 \cdot 1}

j = \frac{- 20 + 2 57}{2 \cdot 1} : - 10 + 57

j = \frac{- 20 - 2 57}{2 \cdot 1} : - 10 - 57

The solutions to the quadratic equation are:

j = - 10 + 57, j = - 10 - 57

z^{2} + 6 z = 1

3^{x} \geq 1

∣ 5 x - 9 ∣ + 9 = 4 x

2 x^{2} - x + 6 = - 4 x + 8

- 48 = 6 (x - 3)

What are the solutions to the equation j^2+20j+43=0 ?
The solutions to the equation j^2+20j+43=0 are j=-10+sqrt(57),j=-10-sqrt(57)
Find the zeros of j^2+20j+43=0
The zeros of j^2+20j+43=0 are j=-10+sqrt(57),j=-10-sqrt(57)