What are the solutions to the equation 3x^2-12x-6=0 ?

The solutions to the equation 3x^2-12x-6=0 are x=2+sqrt(6),x=2-sqrt(6)

Find the zeros of 3x^2-12x-6=0

The zeros of 3x^2-12x-6=0 are x=2+sqrt(6),x=2-sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 12 x - 6 = 0

x = 2 + 6, x = 2 - 6

Decimal Notation

x = 4.44948 \dots, x = - 0.44948 \dots

Solution steps

3 x^{2} - 12 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 6) = 66

x_{1, 2} = \frac{- ( - 12 ) \pm 6 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 6}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 6 6}{2 \cdot 3}

x = \frac{- ( - 12 ) + 6 6}{2 \cdot 3} : 2 + 6

x = \frac{- ( - 12 ) - 6 6}{2 \cdot 3} : 2 - 6

The solutions to the quadratic equation are:

x = 2 + 6, x = 2 - 6

5 x^{2} + 15 x + 30

0.00018 x = 2 π

∣ 2 - x ∣ + 5 = 3

3 x y - 9 x^{2} + 6 x

\frac{x - 1}{4} + \frac{x + 2}{2} < 10

What are the solutions to the equation 3x^2-12x-6=0 ?
The solutions to the equation 3x^2-12x-6=0 are x=2+sqrt(6),x=2-sqrt(6)
Find the zeros of 3x^2-12x-6=0
The zeros of 3x^2-12x-6=0 are x=2+sqrt(6),x=2-sqrt(6)