What is (x^2(8+x)(x-5))/((x+6)(x-2))>= 0 ?

The solution to (x^2(8+x)(x-5))/((x+6)(x-2))>= 0 is x = 5

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(x^2(8+x)(x-5))/((x+6)(x-2))>= 0

\frac{x ^{2} ( 8 + x ) ( x - 5 )}{( x + 6 ) ( x - 2 )} \geq 0

x \leq - 8 or - 6 < x < 2 or x \geq 5

Interval Notation

(- \infty, - 8] \cup (- 6, 2) \cup [5, \infty)

Solution steps

\frac{x ^{2} ( 8 + x ) ( x - 5 )}{( x + 6 ) ( x - 2 )} \geq 0

Identify the intervals

x \leq - 8 or - 6 < x < 2 or x \geq 5

3 lo g_{3} (3)

1 + x + y + x y

\frac{b ^{7}}{b ^{2}}

18 x - (8 x - 7) = 67

x^{5} + 2^{5}

What is (x^2(8+x)(x-5))/((x+6)(x-2))>= 0 ?
The solution to (x^2(8+x)(x-5))/((x+6)(x-2))>= 0 is x<=-8\lor-6<x<2\lor x>= 5