|(5x)/(x+3)-6/(x+3)|>10

Lösung

\frac{5 x}{x + 3} - \frac{6}{x + 3} > 10

- \frac{36}{5} < x < - 3 or - 3 < x < - \frac{8}{5}

Intervall-Notation

(- \frac{36}{5}, - 3) \cup (- 3, - \frac{8}{5})

Dezimale

- 7.2 < x < - 3 or - 3 < x < - 1.6

Schritte zur Lösung

\frac{5 x}{x + 3} - \frac{6}{x + 3} > 10

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

\frac{5 x}{x + 3} - \frac{6}{x + 3} < - 10 or \frac{5 x}{x + 3} - \frac{6}{x + 3} > 10

\frac{5 x}{x + 3} - \frac{6}{x + 3} < - 10 or \frac{5 x}{x + 3} - \frac{6}{x + 3} > 10

- \frac{36}{5} < x < - 3 or - 3 < x < - \frac{8}{5}

f a c t or x y + 1 + x + y

- ∣ 7 - 2 x ∣ - 3 < - 8

f (k) = \frac{- 20 k ^{4} - 26 k ^{3}}{12 k ^{4} + 8 k ^{3}}

f = 2^{2} + 1

f a c t or 4 d^{2} - 4 d - 35