1/(x-2)<1

Lösung

\frac{1}{x - 2} < 1

x < 2 or x > 3

Intervall-Notation

(- \infty, 2) \cup (3, \infty)

Schritte zur Lösung

\frac{1}{x - 2} < 1

Rewrite in standard form

\frac{- x + 3}{x - 2} < 0

Identifiziere die Intervalle

x < 2 or x > 3

z^{2} = - 169

0 = - \frac{1}{2} x^{2} + 4 x - 2

- 172 \leq 2 s

11 x - 37 = 6 (x + 33)

- x^{2} - 4 x - 5 \leq - 2