(x+2)^2(x-6)<0

Lösung

(x + 2)^{2} (x - 6) < 0

x < - 2 or - 2 < x < 6

Intervall-Notation

(- \infty, - 2) \cup (- 2, 6)

Schritte zur Lösung

(x + 2)^{2} (x - 6) < 0

Identifiziere die Intervalle

x < - 2 or - 2 < x < 6

x^{2} = (x - 4)^{2}

s im pl i f y \frac{1}{2} - 4

f = (\frac{1}{6})^{2}

5 x^{2} + 19 x = - 20

x + 2 = 10