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受欢迎的代数 >

化简 22/3(2/3)^{-3}*(-1/3)^{-1}

解答

化简

2 \cdot \frac{2}{3} \cdot (\frac{2}{3})^{- 3} \cdot (- \frac{1}{3})^{- 1}

解答

- \frac{27}{2}

+1

十进制

- 13.5

求解步骤

2 \cdot \frac{2}{3} (\frac{2}{3})^{- 3} (- \frac{1}{3})^{- 1}

\frac{2}{3} (\frac{2}{3})^{- 3} = \frac{1}{\frac{4}{9}}

= 2 \cdot \frac{1}{\frac{4}{9}} (- \frac{1}{3})^{- 1}

使用分式法则:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= 2 \cdot \frac{9}{4} (- \frac{1}{3})^{- 1}

(- \frac{1}{3})^{- 1} = - 3

= 2 (- 3) \frac{9}{4}

去除括号:

(- a) = - a

= - 2 \cdot \frac{9}{4} \cdot 3

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{9 \cdot 2 \cdot 3}{4}

数字相乘:

9 \cdot 2 \cdot 3 = 54

= - \frac{54}{4}

约分:

2

= - \frac{27}{2}

流行的例子

x>=-6-1/4 (-6x+5)

x \geq - 6 - \frac{1}{4} (- 6 x + 5)

12 (x + 8) = 11 x - 5

9 v - 2 = 3 v

s^{2} + s + 1 > 0

x-3<= 1\land 6x>=-24

x - 3 \leq 1 and 6 x \geq - 24