log_{0.3}((x-3)/(1-x))<0

Lösung

lo g_{0.3} (\frac{x - 3}{1 - x}) < 0

1 < x < 2

Intervall-Notation

(1, 2)

Schritte zur Lösung

lo g_{0.3} (\frac{x - 3}{1 - x}) < 0

Wende die log Regel an

\frac{x - 3}{1 - x} > 1

\frac{x - 3}{1 - x} > 1 : 1 < x < 2

1 < x < 2

x (x - 1) (x + 7) > 0

c (c - 6) = 27

6 x + 2 = 2

x^{2} - 4 x = 5

f a c t or - 27 x - 30 x^{4}