faktorisieren t^3-1

Lösung

faktorisieren

t^{3} - 1

(t - 1) (t^{2} + t + 1)

Schritte zur Lösung

t^{3} - 1

Schreibe

1

um:

1^{3}

= t^{3} - 1^{3}

Wende Formel zur Differenz von dritten Potenzen an:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

t^{3} - 1^{3} = (t - 1) (t^{2} + t + 1)

= (t - 1) (t^{2} + t + 1)

11 x = 14

m - 5 \leq 70

- 6 = s - 9

\frac{1}{2} (x + 4) = \frac{3}{4}

\frac{8}{7} x = 56