What is the answer to (x+2)(x+3)(x-1)=(x+4)(x+4)(x-4)-7 ?

The answer to (x+2)(x+3)(x-1)=(x+4)(x+4)(x-4)-7 is x=-65/17

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(x+2)(x+3)(x-1)=(x+4)(x+4)(x-4)-7

(x + 2) (x + 3) (x - 1) = (x + 4) (x + 4) (x - 4) - 7

x = - \frac{65}{17}

Decimal Notation

x = - 3.82352 \dots

Solution steps

(x + 2) (x + 3) (x - 1) = (x + 4) (x + 4) (x - 4) - 7

Simplify

(x + 4) (x + 4) (x - 4) - 7 : (x + 4)^{2} (x - 4) - 7

(x + 2) (x + 3) (x - 1) = (x + 4)^{2} (x - 4) - 7

Expand

(x + 2) (x + 3) : x^{2} + 5 x + 6

(x^{2} + 5 x + 6) (x - 1) = (x + 4)^{2} (x - 4) - 7

Expand

(x^{2} + 5 x + 6) (x - 1) : x^{3} + 4 x^{2} + x - 6

x^{3} + 4 x^{2} + x - 6 = (x + 4)^{2} (x - 4) - 7

Expand

(x + 4)^{2} (x - 4) - 7 : x^{3} + 4 x^{2} - 16 x - 71

x^{3} + 4 x^{2} + x - 6 = x^{3} + 4 x^{2} - 16 x - 71

Move

6

to the right side

x^{3} + 4 x^{2} + x = x^{3} + 4 x^{2} - 16 x - 65

Subtract

x^{3} + 4 x^{2} - 16 x

from both sides

x^{3} + 4 x^{2} + x - (x^{3} + 4 x^{2} - 16 x) = x^{3} + 4 x^{2} - 16 x - 65 - (x^{3} + 4 x^{2} - 16 x)

Simplify

17 x = - 65

Divide both sides by

17

x = - \frac{65}{17}

\frac{3 x ^{3}}{16}

(- \frac{125}{27})^{- \frac{2}{3}}

0 = x^{2} - 8 x + 7

x - \frac{( 2 - x )}{5} \geq 1 - 2 x

40 x + 5

What is the answer to (x+2)(x+3)(x-1)=(x+4)(x+4)(x-4)-7 ?
The answer to (x+2)(x+3)(x-1)=(x+4)(x+4)(x-4)-7 is x=-65/17
Solve for x: (x+2)(x+3)(x-1)=(x+4)(x+4)(x-4)-7
The solution is x=-65/17