faktorisieren x^3+4x-5

Lösung

faktorisieren

x^{3} + 4 x - 5

(x - 1) (x^{2} + x + 5)

Schritte zur Lösung

x^{3} + 4 x - 5

Wende den rationalen Nullstellentest an

= (x - 1) \frac{x ^{3} + 4 x - 5}{x - 1}

\frac{x ^{3} + 4 x - 5}{x - 1} = x^{2} + x + 5

= (x - 1) (x^{2} + x + 5)

\frac{x}{9} = \frac{8}{12}

2 (4 - 2 x) + 2 (2 x - 4) \geq 2 x

- 13 \geq 1 + 5 n - 4

7^{2} + x^{2} = 1 2^{2}

1 > 4