What are the solutions to the equation n^2-2n-61=-7 ?

The solutions to the equation n^2-2n-61=-7 are n=1+sqrt(55),n=1-sqrt(55)

Find the zeros of n^2-2n-61=-7

The zeros of n^2-2n-61=-7 are n=1+sqrt(55),n=1-sqrt(55)

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n^{2} - 2 n - 61 = - 7

n = 1 + 55, n = 1 - 55

Decimal Notation

n = 8.41619 \dots, n = - 6.41619 \dots

Solution steps

n^{2} - 2 n - 61 = - 7

Move

7

to the left side

n^{2} - 2 n - 54 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 54) = 255

n_{1, 2} = \frac{- ( - 2 ) \pm 2 55}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 2 ) + 2 55}{2 \cdot 1}, n_{2} = \frac{- ( - 2 ) - 2 55}{2 \cdot 1}

n = \frac{- ( - 2 ) + 2 55}{2 \cdot 1} : 1 + 55

n = \frac{- ( - 2 ) - 2 55}{2 \cdot 1} : 1 - 55

The solutions to the quadratic equation are:

n = 1 + 55, n = 1 - 55

(- 0.2)^{2}

4 x^{2} - 8 x + 7 = 0

5 u \leq 8 u - 21

x - 9 \leq - 8

\frac{x}{5} + x = 180

What are the solutions to the equation n^2-2n-61=-7 ?
The solutions to the equation n^2-2n-61=-7 are n=1+sqrt(55),n=1-sqrt(55)
Find the zeros of n^2-2n-61=-7
The zeros of n^2-2n-61=-7 are n=1+sqrt(55),n=1-sqrt(55)