|4x|>5

Lösung

∣ 4 x ∣ > 5

x < - \frac{5}{4} or x > \frac{5}{4}

Intervall-Notation

(- \infty, - \frac{5}{4}) \cup (\frac{5}{4}, \infty)

Dezimale

x < - 1.25 or x > 1.25

Schritte zur Lösung

∣ 4 x ∣ > 5

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

4 x < - 5 or 4 x > 5

4 x < - 5 or 4 x > 5

x < - \frac{5}{4} or x > \frac{5}{4}

f a c t or x^{3} - 9 x^{2} + 20 x - 12

\frac{4}{5} > \frac{2}{3} - \frac{2}{7} x

- 8 \leq 2 x - 4 < 4

- 7 + 4 x = 37

x = 2 x (1 - x)