v^2-8v+12=0

解

v^{2} - 8 v + 12 = 0

v = 6, v = 2

解答ステップ

v^{2} - 8 v + 12 = 0

解くとthe二次式

v_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 12 = 4

v_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 1}

解を分離する

v_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 1}, v_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 1}

v = \frac{- ( - 8 ) + 4}{2 \cdot 1} : 6

v = \frac{- ( - 8 ) - 4}{2 \cdot 1} : 2

二次equationの解:

v = 6, v = 2