vereinfachen (2b)^{7/4}

Lösung

vereinfachen

(2 b)^{\frac{7}{4}}

2 \cdot 2^{\frac{3}{4}} b^{\frac{7}{4}}

Schritte zur Lösung

(2 b)^{\frac{7}{4}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(2 b)^{\frac{7}{4}} = 2^{\frac{7}{4}} b^{\frac{7}{4}}

= 2^{\frac{7}{4}} b^{\frac{7}{4}}

2^{\frac{7}{4}} = 2 \cdot 2^{\frac{3}{4}}

= 2 \cdot 2^{\frac{3}{4}} b^{\frac{7}{4}}

7 x - 1 = 2 x + 5

s im pl i f y \frac{- 2 + - 8}{2}

3 x^{3} - 48 x < x^{2} - 16

x^{2} - 4 x + 3 = 2

\frac{4}{x ^{2}} < \frac{5}{x ^{3}}