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受欢迎的代数 >

x^2+(0.012x)-(0.0006996)=0

解答

x^{2} + (0.012 x) - (0.0006996) = 0

解答

x = \frac{- 0.012 + 0.0029424}{2}, x = \frac{- 0.012 - 0.0029424}{2}

+1

十进制

x = 0.02112 \dots, x = - 0.03312 \dots

求解步骤

x^{2} + (0.012 x) - (0.0006996) = 0

整理后得

x^{2} + 0.012 x - 0.0006996 = 0

使用求根公式求解

x_{1, 2} = \frac{- 0.012 \pm 0.01 2 ^{2} - 4 \cdot 1 \cdot ( - 0.0006996 )}{2 \cdot 1}

0.01 2^{2} - 4 \cdot 1 \cdot (- 0.0006996) = 0.0029424

x_{1, 2} = \frac{- 0.012 \pm 0.0029424}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- 0.012 + 0.0029424}{2 \cdot 1}, x_{2} = \frac{- 0.012 - 0.0029424}{2 \cdot 1}

x = \frac{- 0.012 + 0.0029424}{2 \cdot 1} : \frac{- 0.012 + 0.0029424}{2}

x = \frac{- 0.012 - 0.0029424}{2 \cdot 1} : \frac{- 0.012 - 0.0029424}{2}

二次方程组的解是:

x = \frac{- 0.012 + 0.0029424}{2}, x = \frac{- 0.012 - 0.0029424}{2}

作图

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