2t^2-24t+70=0

解

2 t^{2} - 24 t + 70 = 0

t = 7, t = 5

解答ステップ

2 t^{2} - 24 t + 70 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 2 \cdot 70}{2 \cdot 2}

(- 24)^{2} - 4 \cdot 2 \cdot 70 = 4

t_{1, 2} = \frac{- ( - 24 ) \pm 4}{2 \cdot 2}

解を分離する

t_{1} = \frac{- ( - 24 ) + 4}{2 \cdot 2}, t_{2} = \frac{- ( - 24 ) - 4}{2 \cdot 2}

t = \frac{- ( - 24 ) + 4}{2 \cdot 2} : 7

t = \frac{- ( - 24 ) - 4}{2 \cdot 2} : 5

二次equationの解:

t = 7, t = 5