What is the domain of f(n)=((3*2^n)*(3*8^n))/(3*16^{1-n)} ?

The domain of f(n)=((3*2^n)*(3*8^n))/(3*16^{1-n)} is -infinity <n<infinity

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domain of f(n)=((32^n)(38^n))/(316^{1-n)}

domain

f (n) = \frac{( 3 \cdot 2 ^{n} ) \cdot ( 3 \cdot 8 ^{n} )}{3 \cdot 1 6 ^{1 - n}}

- \infty < n < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < n < \infty

844

4 x^{2} - 12 x + 5 = 0

2 x^{2} + 4 = x

4 b^{2} - 21 b + 5

20 = 5 h

What is the domain of f(n)=((3*2^n)*(3*8^n))/(3*16^{1-n)} ?
The domain of f(n)=((3*2^n)*(3*8^n))/(3*16^{1-n)} is -infinity <n<infinity