What are the solutions to the equation x^2-1.3x+0.12=0 ?

The solutions to the equation x^2-1.3x+0.12=0 are x= 6/5 ,x= 1/10

Find the zeros of x^2-1.3x+0.12=0

The zeros of x^2-1.3x+0.12=0 are x= 6/5 ,x= 1/10

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x^{2} - 1.3 x + 0.12 = 0

x = \frac{6}{5}, x = \frac{1}{10}

Decimal Notation

x = 1.2, x = 0.1

Solution steps

x^{2} - 1.3 x + 0.12 = 0

Multiply both sides by

100

100 x^{2} - 130 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 130 ) \pm ( - 130 ) ^{2} - 4 \cdot 100 \cdot 12}{2 \cdot 100}

(- 130)^{2} - 4 \cdot 100 \cdot 12 = 110

x_{1, 2} = \frac{- ( - 130 ) \pm 110}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 130 ) + 110}{2 \cdot 100}, x_{2} = \frac{- ( - 130 ) - 110}{2 \cdot 100}

x = \frac{- ( - 130 ) + 110}{2 \cdot 100} : \frac{6}{5}

x = \frac{- ( - 130 ) - 110}{2 \cdot 100} : \frac{1}{10}

The solutions to the quadratic equation are:

x = \frac{6}{5}, x = \frac{1}{10}

x^{2} - 4 x + 16 = 0

9 = y^{2}

(\frac{1}{2})^{2} - 2

- f - (9 f + 10) \leq 6 f + 7 - 3

y + 4 \leq 6

What are the solutions to the equation x^2-1.3x+0.12=0 ?
The solutions to the equation x^2-1.3x+0.12=0 are x= 6/5 ,x= 1/10
Find the zeros of x^2-1.3x+0.12=0
The zeros of x^2-1.3x+0.12=0 are x= 6/5 ,x= 1/10