((x+5)(2x-7))/((x+1)^2)<= 0

解答

\frac{( x + 5 ) ( 2 x - 7 )}{( x + 1 ) ^{2}} \leq 0

- 5 \leq x < - 1 or - 1 < x \leq \frac{7}{2}

间隔符号

[- 5, - 1) \cup (- 1, \frac{7}{2}]

十进制

- 5 \leq x < - 1 or - 1 < x \leq 3.5

求解步骤

\frac{( x + 5 ) ( 2 x - 7 )}{( x + 1 ) ^{2}} \leq 0

确定区间

- 5 \leq x < - 1 or - 1 < x \leq \frac{7}{2}

f a c t or u^{2} - 10 u + 25

f a c t or 5 t + 30

- 4.8 (6.3 x - 4.18) = - 58.56

2 a + 5 \geq 17

5 y - 2 (4 - y) = 27 + 1 - 2 (2 y - 4) - 1