faktorisieren m^2n^2+mn^2-2m^2n

Lösung

faktorisieren

m^{2} n^{2} + m n^{2} - 2 m^{2} n

mn (mn + n - 2 m)

Schritte zur Lösung

m^{2} n^{2} + m n^{2} - 2 m^{2} n

Wende Exponentenregel an:

a^{b + c} = a^{b} a^{c}

m^{2} n^{2} = mmnn, m n^{2} = mnn, m^{2} n = mmn

= mmnn + mnn - 2 mmn

Klammere gleiche Terme aus

mn

= mn (mn + n - 2 m)

(\frac{1}{N} + \frac{0.0004}{1 - 0.0004 N}) d N = d t

x^{2} - 10 x + 24 > 0

\frac{5 x - 4}{4} = \frac{x - 5}{5}

f a c t or 5 a^{6} - 16 a^{5} - 45 a^{4}

\frac{2}{5} (5 x - 1) + \frac{3}{10} (10 x - 3) = - \frac{1}{2} (x - 2) - \frac{6}{5}