What are the solutions to the equation 4+x^2=0 ?

The solutions to the equation 4+x^2=0 are x=2i,x=-2i

Find the zeros of 4+x^2=0

The zeros of 4+x^2=0 are x=2i,x=-2i

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4 + x^{2} = 0

x = 2 i, x = - 2 i

Solution steps

4 + x^{2} = 0

Move

4

to the right side

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

10 x^{2} - 15 x = 0

\frac{x}{7} > - 2

2 x + 3 = 13

- 25 r^{2} + 1

3 5^{2} + 1 2^{2}

What are the solutions to the equation 4+x^2=0 ?
The solutions to the equation 4+x^2=0 are x=2i,x=-2i
Find the zeros of 4+x^2=0
The zeros of 4+x^2=0 are x=2i,x=-2i