What are the solutions to the equation x^2-18x-40=0 ?

The solutions to the equation x^2-18x-40=0 are x=20,x=-2

Find the zeros of x^2-18x-40=0

The zeros of x^2-18x-40=0 are x=20,x=-2

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x^{2} - 18 x - 40 = 0

x = 20, x = - 2

Solution steps

x^{2} - 18 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot (- 40) = 22

x_{1, 2} = \frac{- ( - 18 ) \pm 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 22}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 22}{2 \cdot 1}

x = \frac{- ( - 18 ) + 22}{2 \cdot 1} : 20

x = \frac{- ( - 18 ) - 22}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 20, x = - 2

9 x^{2} = 4

x^{2} + 75 = 0

ln^{2} (e)

1.6 x^{2} = 3 x

x^{2} + (x - 6)^{2} = 20

What are the solutions to the equation x^2-18x-40=0 ?
The solutions to the equation x^2-18x-40=0 are x=20,x=-2
Find the zeros of x^2-18x-40=0
The zeros of x^2-18x-40=0 are x=20,x=-2