p^2+4p-12=0

解

p^{2} + 4 p - 12 = 0

p = 2, p = - 6

解答ステップ

p^{2} + 4 p - 12 = 0

解くとthe二次式

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 12) = 8

p_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 1}

解を分離する

p_{1} = \frac{- 4 + 8}{2 \cdot 1}, p_{2} = \frac{- 4 - 8}{2 \cdot 1}

p = \frac{- 4 + 8}{2 \cdot 1} : 2

p = \frac{- 4 - 8}{2 \cdot 1} : - 6

二次equationの解:

p = 2, p = - 6