faktorisieren 1-1/8 p^3

Lösung

faktorisieren

1 - \frac{1}{8} p^{3}

- (\frac{p}{2} - 1) (\frac{p ^{2}}{4} + \frac{p}{2} + 1)

Schritte zur Lösung

1 - \frac{1}{8} p^{3}

Faktorisiere

1 - \frac{p ^{3}}{8} : - (\frac{p}{2} - 1) ((\frac{1}{2})^{2} p^{2} + \frac{1}{2} p + 1)

= - (\frac{p}{2} - 1) ((\frac{1}{2})^{2} p^{2} + \frac{1}{2} p + 1)

Vereinfache

- (\frac{p}{2} - 1) ((\frac{1}{2})^{2} p^{2} + \frac{1}{2} p + 1) : - (\frac{p}{2} - 1) (\frac{p ^{2}}{4} + \frac{p}{2} + 1)

= - (\frac{p}{2} - 1) (\frac{p ^{2}}{4} + \frac{p}{2} + 1)

- 8 x + 2 = 2 x - 2

s im pl i f y \frac{48}{60}

f a c t or 9 x^{2} + 66 x y + 121 y^{2}

3 x - 2 > 1

u^{2} = - 36