What are the solutions to the equation (x+5)(x+8)=0 ?

The solutions to the equation (x+5)(x+8)=0 are x=-5,x=-8

Find the zeros of (x+5)(x+8)=0

The zeros of (x+5)(x+8)=0 are x=-5,x=-8

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(x + 5) (x + 8) = 0

x = - 5, x = - 8

Solution steps

(x + 5) (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or x + 8 = 0

Solve

x + 5 = 0 : x = - 5

Solve

x + 8 = 0 : x = - 8

The solutions to the quadratic equation are:

x = - 5, x = - 8

(x - 6)^{2} = 7

45 x^{2} - 20 y^{2}

(4 z)^{- 3} \cdot (2 z)^{5}

- 3 < 2 x + 1 \leq 3

z^{2} - 14 z + 49

What are the solutions to the equation (x+5)(x+8)=0 ?
The solutions to the equation (x+5)(x+8)=0 are x=-5,x=-8
Find the zeros of (x+5)(x+8)=0
The zeros of (x+5)(x+8)=0 are x=-5,x=-8