What are the solutions to the equation 4(x-1)^2=8 ?

The solutions to the equation 4(x-1)^2=8 are x=sqrt(2)+1,x=-sqrt(2)+1

Find the zeros of 4(x-1)^2=8

The zeros of 4(x-1)^2=8 are x=sqrt(2)+1,x=-sqrt(2)+1

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4 (x - 1)^{2} = 8

x = 2 + 1, x = - 2 + 1

Decimal Notation

x = 2.41421 \dots, x = - 0.41421 \dots

Solution steps

4 (x - 1)^{2} = 8

Divide both sides by

4

(x - 1)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 2 : x = 2 + 1

Solve

x - 1 = - 2 : x = - 2 + 1

The solutions to the quadratic equation are:

x = 2 + 1, x = - 2 + 1

(a + b + 1) (a^{2} + 1) - a^{2} - 1

11 = \frac{4000}{127000}

\frac{5}{9} - \frac{9}{5}

\frac{1}{2}

1 + \frac{2 x}{5} - \frac{1}{2} (x + 5) \geq x

What are the solutions to the equation 4(x-1)^2=8 ?
The solutions to the equation 4(x-1)^2=8 are x=sqrt(2)+1,x=-sqrt(2)+1
Find the zeros of 4(x-1)^2=8
The zeros of 4(x-1)^2=8 are x=sqrt(2)+1,x=-sqrt(2)+1