integral of cxy+1/4

Lösung

\int c x y + \frac{1}{4}

\frac{1}{4} x + \frac{cy x ^{2}}{2} + C

Schritte zur Lösung

\int c x y + \frac{1}{4} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{4} d x + \int cy x d x

\int \frac{1}{4} d x = \frac{1}{4} x

\int cy x d x = \frac{cy x ^{2}}{2}

= \frac{1}{4} x + \frac{cy x ^{2}}{2}

Füge eine Konstante zur Lösung hinzu

= \frac{1}{4} x + \frac{cy x ^{2}}{2} + C

t an g e n t f (x) = \frac{x}{4 x - 7}, at x = 1

t an g e n t - 5 x^{2} + x - 2

\int_{0}^{9} \frac{1}{81 + x ^{2}} d x

y^{^{''}} + 4 y^{^{'}} + 5 y = - 20 e^{t}, y (0) = - 4, y^{^{'}} (0) = 1

\int_{1}^{4} 6 e^{x} d x