(dy)/(dx)=e^{3x}+9y

Lösung

\frac{d y}{d x} = e^{3 x} + 9 y

y = - \frac{e ^{3 x}}{6} + c_{1} e^{9 x}

Schritte zur Lösung

\frac{d y}{d x} = e^{3 x} + 9 y

Solve linear ODE:

y = - \frac{e ^{3 x}}{6} + c_{1} e^{9 x}

y = - \frac{e ^{3 x}}{6} + c_{1} e^{9 x}

x \to - 2 lim (\frac{sin ( - π x )}{2 + x})

\int_{2}^{3} \frac{22}{3 - x} d x

t an g e n t f (x) = x^{3} - 4 x, at x = 0

in v erse l a pl a ce \frac{2}{( s + 2 )}

d er i v a t i v e ln (\frac{( 8 x - 9 ) ^{2}}{- x - 1})