(1+e^x)yy^'=e^x,y(0)=1

Lösung

(1 + e^{x}) y y^{^{'}} = e^{x}, y (0) = 1

y = 2 ln (1 + e^{x}) + 1 - 2 ln (2)

Schritte zur Lösung

(1 + e^{x}) y y^{'} (x) = e^{x}

Solve separable ODE:

y = 2 ln (1 + e^{x}) + 1 - 2 ln (2)

y = 2 ln (1 + e^{x}) + 1 - 2 ln (2)

d er i v a t i v e f (x) = 3 x^{2} - 8 x - x

x \to - 3 lim (x^{3} - 4 x^{2} - 7)

n = 1 \sum \infty \frac{n - 9}{n + 9}

in v erse l a pl a ce \frac{( 11 s ^{2} - 2 s + 5 )}{( s - 2 ) ( 2 s - 1 ) ( s + 1 )}

l a pl a ce t r an s f or m - 3 t