y^'=sin(y)

Lösung

y^{^{'}} = sin (y)

y = 2 arctan (e^{t + c_{1}}) + 2 πn

Schritte zur Lösung

y^{'} (t) = sin (y)

Solve separable ODE:

y = 2 arctan (e^{t + c_{1}}) + 2 πn

y = 2 arctan (e^{t + c_{1}}) + 2 πn

\int \frac{8 t ^{3} - 3 t ^{2} + 32 t}{t ^{2} + 4} d t

\frac{\partial}{\partial y} (x^{7 y})

\frac{d}{d x} (ln (- 2 x))

\int - \frac{8 x ^{3}}{( 5 - 2 x ^{4} ) ^{4}} d x

10 y^{^{''}} - y^{^{'}} - 3 y = 0, y (0) = 1, y^{^{'}} (0) = 0