integral of (x+5)(x^2+5x-10)

Lösung

\int (x + 5) (x^{2} + 5 x - 10) d x

\frac{x ^{4}}{4} + \frac{10 x ^{3}}{3} + \frac{15 x ^{2}}{2} - 50 x + C

Schritte zur Lösung

\int (x + 5) (x^{2} + 5 x - 10) d x

Multipliziere aus

(x + 5) (x^{2} + 5 x - 10) : x^{3} + 10 x^{2} + 15 x - 50

= \int x^{3} + 10 x^{2} + 15 x - 50 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x + \int 10 x^{2} d x + \int 15 x d x - \int 50 d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 10 x^{2} d x = \frac{10 x ^{3}}{3}

\int 15 x d x = \frac{15 x ^{2}}{2}

\int 50 d x = 50 x

= \frac{x ^{4}}{4} + \frac{10 x ^{3}}{3} + \frac{15 x ^{2}}{2} - 50 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{4}}{4} + \frac{10 x ^{3}}{3} + \frac{15 x ^{2}}{2} - 50 x + C

t a y l or u^{2}

\frac{\partial}{\partial x} (3 x y)

\int_{1}^{4} - 7 t ln (t) d t

\frac{d}{d x} (\frac{2 x ^{3} + 4}{x ^{2} - 4 x + 1})

x \to 0 lim (ln (tan (7 x)))