derivative x^2+6x+3

解答

导数

x^{2} + 6 x + 3

2 x + 6

求解步骤

\frac{d}{d x} (x^{2} + 6 x + 3)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (3) = 0

= 2 x + 6 + 0

化简

= 2 x + 6

\frac{d}{d x} (3 \frac{1 + x ^{3}}{1 - x ^{3}})

x \to 8 + lim (ln (x^{2} - 64))

t a y l or \frac{1}{1 - x}, 1.1

in v erse l a pl a ce \frac{3}{( s + 2 ) \cdot ( 4 s ^{2} + 4 s + 5 )}

\frac{d}{d x} (x^{4} - 3 x^{3} + 2 x^{2})