f^'(x)=12x^3-63x^2-72x+4

解

f^{^{'}} (x) = 12 x^{3} - 63 x^{2} - 72 x + 4

f (x) = 3 x^{4} - 21 x^{3} - 36 x^{2} + 4 x + c_{1}

解答ステップ

f^{'} (x) = 12 x^{3} - 63 x^{2} - 72 x + 4

f^{^{'}} (x) = g (x)

であれば

f (x) = \int g (x) d x

f (x) = \int 12 x^{3} - 63 x^{2} - 72 x + 4 d x

\int 12 x^{3} - 63 x^{2} - 72 x + 4 d x = 3 x^{4} - 21 x^{3} - 36 x^{2} + 4 x + c_{1}

f (x) = 3 x^{4} - 21 x^{3} - 36 x^{2} + 4 x + c_{1}