derivative of x^4+cos(x+1)

Lösung

\frac{d}{d x} (x^{4} + cos (x) + 1)

4 x^{3} - sin (x)

Schritte zur Lösung

\frac{d}{d x} (x^{4} + cos (x) + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (cos (x)) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (cos (x)) = - sin (x)

\frac{d}{d x} (1) = 0

= 4 x^{3} - sin (x) + 0

Vereinfache

= 4 x^{3} - sin (x)

\int \frac{( 16 - 9 x ^{2} ) ^{\frac{3}{2}}}{x ^{6}} d x

n = 1 \sum \infty (\frac{( 3 n - 1 )}{( 3 n )})^{n^{2}}

tan (x) sin^{2} (y) d x + cos^{2} (x) cot (y) d y = 0

n = 0 \sum \infty 1 + \frac{1}{n ^{2}}

\int_{- 2}^{2} x^{2} e^{x^{3} + 8} d x