What is the derivative of 1-e^{3x} ?

The derivative of 1-e^{3x} is -3e^{3x}

What is the first derivative of 1-e^{3x} ?

The first derivative of 1-e^{3x} is -3e^{3x}

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\frac{d}{d x} (1 - e^{3 x})

- 3 e^{3 x}

Solution steps

\frac{d}{d x} (1 - e^{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (e^{3 x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (e^{3 x}) = e^{3 x} \cdot 3

= 0 - e^{3 x} \cdot 3

Simplify

= - 3 e^{3 x}

\int_{1}^{2} \frac{x ^{2} - 1}{x} d x

l a pl a ce t r an s f or m t cos (2 t)

k = 0 \sum \infty (\frac{e}{10})^{k}

x \to 1 - lim (- x^{2} + 3 x - 4)

\frac{d}{d x} (e^{x} (cos (x)))

What is the derivative of 1-e^{3x} ?
The derivative of 1-e^{3x} is -3e^{3x}
What is the first derivative of 1-e^{3x} ?
The first derivative of 1-e^{3x} is -3e^{3x}