What is the integral of 5xln(x) ?

The integral of 5xln(x) is 5(1/2 x^2ln(x)-(x^2)/4)+C

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integral of 5xln(x)

\int 5 x ln (x) d x

5 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4}) + C

Solution steps

\int 5 x ln (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int x ln (x) d x

Apply Integration By Parts

= 5 (\frac{1}{2} x^{2} ln (x) - \int \frac{x}{2} d x)

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= 5 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4})

Add a constant to the solution

= 5 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4}) + C

t an g e n t f (x) = - \frac{1}{x}, at x = 3

x \to - 4 lim (- x^{2} + 6 x - 8)

\frac{d}{d x} (\frac{x}{x - 8})

\frac{d}{d t} (4 cos (2 t))

y^{^{'}} = \frac{x}{y} + \frac{y}{x}

What is the integral of 5xln(x) ?
The integral of 5xln(x) is 5(1/2 x^2ln(x)-(x^2)/4)+C