xy^'+2y=-4sin(x)

Lösung

x y^{^{'}} + 2 y = - 4 sin (x)

y = - \frac{4 ( - x cos ( x ) + sin ( x ) )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

Schritte zur Lösung

x y^{'} (x) + 2 y = - 4 sin (x)

Solve linear ODE:

y = - \frac{4 ( - x cos ( x ) + sin ( x ) )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

y = - \frac{4 ( - x cos ( x ) + sin ( x ) )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

\int \frac{sec ^{4} ( t )}{tan ^{2} ( t )} d t

\frac{d}{d x} (\frac{x ^{2} + 2 x}{4 - 5 x})

t an g e n t f (x) = tan (x), at x = \frac{π}{4}

x \to 0 lim (\frac{cos ( 7 x ) tan ( 7 x )}{x})

\frac{\partial}{\partial y} (e^{x y})