y^'+2y=3,y(0)=0

Lösung

y^{^{'}} + 2 y = 3, y (0) = 0

y = - \frac{3 e ^{- 2 t}}{2} + \frac{3}{2}

Schritte zur Lösung

y^{'} (t) + 2 y = 3

Solve separable ODE:

y = - \frac{3 e ^{- 2 t}}{2} + \frac{3}{2}

y = - \frac{3 e ^{- 2 t}}{2} + \frac{3}{2}

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