6y^{''}+y^'-y=0,y(0)=-1,y^'(0)=3

Lösung

6 y^{^{''}} + y^{^{'}} - y = 0, y (0) = - 1, y^{^{'}} (0) = 3

y = 3 e^{\frac{t}{3}} - 4 e^{- \frac{t}{2}}

Schritte zur Lösung

6 y^{''} (t) + y^{'} (t) - y = 0

Solve linear ODE:

y = 3 e^{\frac{t}{3}} - 4 e^{- \frac{t}{2}}

y = 3 e^{\frac{t}{3}} - 4 e^{- \frac{t}{2}}

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