What is the tangent of 6x^2-3x+4 ?

The tangent of 6x^2-3x+4 is y=(12a_{0}-3)x-6a_{0}^2+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 6x^2-3x+4

tangent of

6 x^{2} - 3 x + 4

y = (12 a_{0} - 3) x - 6 a_{0}^{2} + 4

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 6 a_{0}^{2} - 3 a_{0} + 4)

Find the slope of

y = 6 x^{2} - 3 x + 4 : \frac{d y}{d x} = 12 x - 3

Compute the slope of

y = 6 x^{2} - 3 x + 4

x = a_{0} : m = 12 a_{0} - 3

Find the line with slope m=

12 a_{0} - 3

and passing through

(a_{0}, 6 a_{0}^{2} - 3 a_{0} + 4) : y = (12 a_{0} - 3) x - 6 a_{0}^{2} + 4

y = (12 a_{0} - 3) x - 6 a_{0}^{2} + 4

\int \frac{x + 6}{x - 3} d x

2 x (y + 1) - y y^{^{'}} = 0

\int_{- 2}^{2} \frac{1}{x ^{2} + 4 x + 13} d x

\int x e - x^{2} d x

f (x) = (8 - x)^{3}

What is the tangent of 6x^2-3x+4 ?
The tangent of 6x^2-3x+4 is y=(12a_{0}-3)x-6a_{0}^2+4