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Popular Calculus >

y^'+e^xy=2e^x

Solution

y^{^{'}} + e^{x} y = 2 e^{x}

Solution

y = - e^{- e^{x} - c_{1}} + 2

Solution steps

y^{'} (x) + e^{x} y = 2 e^{x}

Solve separable ODE:

y = - e^{- e^{x} - c_{1}} + 2

y = - e^{- e^{x} - c_{1}} + 2

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+e^xy=2e^x ?
The solution for y^'+e^xy=2e^x is y=-e^{-e^x-c_{1}}+2