What is the derivative of y=3x^2+1/x ?

The derivative of y=3x^2+1/x is 6x-1/(x^2)

What is the first derivative of y=3x^2+1/x ?

The first derivative of y=3x^2+1/x is 6x-1/(x^2)

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derivative of

y = 3 x^{2} + \frac{1}{x}

6 x - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (3 x^{2} + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 6 x - \frac{1}{x ^{2}}

\int 7 cos^{3} (3 x) d x

d er i v a t i v e f (x) = cos (2 sin (x))

\frac{d}{d x} (ln (x + 4 + x^{2}))

l a pl a ce t r an s f or m 5 cos (2 t)

\frac{d}{d x} (sin^{3} (2 x) + x^{2})

What is the derivative of y=3x^2+1/x ?
The derivative of y=3x^2+1/x is 6x-1/(x^2)
What is the first derivative of y=3x^2+1/x ?
The first derivative of y=3x^2+1/x is 6x-1/(x^2)